# program to check Armstrong number in java

#### Learn Java Programming for Beginners

Armstrong number is a number which is equal to sum of digits raise to the power total number of digits in the number.

example :

2=2^1

153=1^3+5^3+3^3=(1+125+27=153)

**Program to check whether the number is an Armstrong number in java**

class armstrong

{

public static void main(String args[])throws IOException

{

int sum=0,ch,i,j,num,no;

DataInputStream in=new DataInputStream(System.in);

no= Integer.parseInt(in.readLine());

num=no;

do

{

sum=sum+(no%10)*(no%10)*(no%10);

no=no/10;

}

while(no!=0);

if(sum==num)

System.out.println(“The number “+num+” is an Armstrong number “);

else

System.out.println(“The number “+num+” is not an Armstrong number “);

}

}

output:

Another way to check if a number is an Armstrong number by taking user input..

package com.practice.java;

import java.util.Scanner;

class Armstrong{

public static void main(String args[]){

System.out.println(“Enter a number”);

Scanner sc = new Scanner(System.in);

String a = sc.nextLine();

int size = a.length();

System.out.println(“Length of the input number is = ” + size);

int num = Integer.parseInt(a);

int n = num;

int check=0,remainder;

while(num > 0){

remainder = num % 10;

check = check + (int)Math.pow(remainder,size);

num = num / 10;

}

if(check == n)

System.out.println(n+” is an Armstrong Number”);

else

System.out.println(n+” is not an Armstrong Number”);

sc.close();

}

}

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